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Some educated guess

farnaws

Star Member
Jan 26, 2015
77
0
Based on previous draws, I fitted a linear regression model that can predict the scores for next draws based on number of people selected at each of them. I assumed that in the next draw(s) number of people would be anywhere between 700 to 2500. Based on the assumption, here are some predictions:

#of People Selected Predicted Scores
700 500
750 499
800 497
850 496
900 494
950 492
1000 491
1050 489
1100 488
1150 486
1200 484
1250 483
1300 481
1350 480
1400 478
1450 477
1500 475
2000 459
2200 453
2300 450
2500 443

It seems like to reach score 450, 2300 people needs to be selected. Its a linear regression model and it will perform better and better based on number of data points its been trained on. Right now, there have been 42 draws. So I felt like we have atleast not a bad amount of data to fit a regression model.
 

prads_s

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Aug 17, 2016
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It might just me worth to evaluate pattern of last year and apply similar pattern to future draws
 

Sluffy

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May 11, 2016
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dan_and said:
Good effort, but unfortunately, a linear regression is useless for this problem.
Exactly.
After 481 it does not work at all, because many people stuck there since May
 

mead

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farnaws said:
Based on previous draws, I fitted a linear regression model that can predict the scores for next draws based on number of people selected at each of them. I assumed that in the next draw(s) number of people would be anywhere between 700 to 2500. Based on the assumption, here are some predictions:

#of People Selected Predicted Scores
700 500
750 499
800 497
850 496
900 494
950 492
1000 491
1050 489
1100 488
1150 486
1200 484
1250 483
1300 481
1350 480
1400 478
1450 477
1500 475
2000 459
2200 453
2300 450
2500 443

It seems like to reach score 450, 2300 people needs to be selected. Its a linear regression model and it will perform better and better based on number of data points its been trained on. Right now, there have been 42 draws. So I felt like we have atleast not a bad amount of data to fit a regression model. Also, I am attaching the graph of the linear fit.
my educated guess ur CRS is 444? just a guess. Jokes apart good effort
 

farnaws

Star Member
Jan 26, 2015
77
0
mead said:
my educated guess ur CRS is 444? just a guess. Jokes apart good effort
Thank you :D. I have landed this year at May as a PR. However, I am extremely grateful to this group and always look for ways to help the aspirants...

Anyways, I know it's not easy to build a robust model since we don't know the nature of distribution, yet it's simple and its not bad at all. At yesterdays draw, for 1288 people it predicted a score of 482, exact score was 483.

Best of luck fellows!
 

Fabby12

Full Member
Sep 21, 2016
34
0
farnaws said:
Thank you :D. I have landed this year at May as a PR. However, I am extremely grateful to this group and always look for ways to help the aspirants...

Anyways, I know it's not easy to build a robust model since we don't know the nature of distribution, yet it's simple and its not bad at all. At yesterdays draw, for 1288 people it predicted a score of 482, exact score was 483.

Best of luck fellows!
can you help me??? I m confused while calculating my points...